Answer :
To determine the total number of valence electrons in the perbromate ion, [tex]\( BrO_4^- \)[/tex], let's follow these steps:
1. Identify the number of valence electrons in a bromine atom:
- Bromine (Br) is in group 17 of the periodic table.
- Therefore, it has 7 valence electrons.
2. Identify the number of valence electrons in an oxygen atom:
- Oxygen (O) is in group 16 of the periodic table.
- Therefore, each oxygen atom has 6 valence electrons.
3. Determine the number of oxygen atoms in the ion:
- The perbromate ion ([tex]\( BrO_4^- \)[/tex]) has 4 oxygen atoms.
4. Account for the extra electron due to the negative charge of the ion:
- The ion has a [tex]\( -1 \)[/tex] charge, which means there is one additional electron.
5. Sum up all the valence electrons:
- Valence electrons from bromine: [tex]\( 7 \)[/tex]
- Valence electrons from the 4 oxygen atoms: [tex]\( 4 \times 6 = 24 \)[/tex]
- Additional electron from the [tex]\( -1 \)[/tex] charge: [tex]\( 1 \)[/tex]
6. Calculate the total number of valence electrons:
- Total valence electrons [tex]\( = 7 + 24 + 1 \)[/tex]
- Total valence electrons [tex]\( = 32 \)[/tex]
So, the total number of valence electrons in the perbromate ion [tex]\( BrO_4^- \)[/tex] is [tex]\( 32 \)[/tex].
1. Identify the number of valence electrons in a bromine atom:
- Bromine (Br) is in group 17 of the periodic table.
- Therefore, it has 7 valence electrons.
2. Identify the number of valence electrons in an oxygen atom:
- Oxygen (O) is in group 16 of the periodic table.
- Therefore, each oxygen atom has 6 valence electrons.
3. Determine the number of oxygen atoms in the ion:
- The perbromate ion ([tex]\( BrO_4^- \)[/tex]) has 4 oxygen atoms.
4. Account for the extra electron due to the negative charge of the ion:
- The ion has a [tex]\( -1 \)[/tex] charge, which means there is one additional electron.
5. Sum up all the valence electrons:
- Valence electrons from bromine: [tex]\( 7 \)[/tex]
- Valence electrons from the 4 oxygen atoms: [tex]\( 4 \times 6 = 24 \)[/tex]
- Additional electron from the [tex]\( -1 \)[/tex] charge: [tex]\( 1 \)[/tex]
6. Calculate the total number of valence electrons:
- Total valence electrons [tex]\( = 7 + 24 + 1 \)[/tex]
- Total valence electrons [tex]\( = 32 \)[/tex]
So, the total number of valence electrons in the perbromate ion [tex]\( BrO_4^- \)[/tex] is [tex]\( 32 \)[/tex].